one to a million of numbers

[Newt]

Little Tinca:

Fancy posting without her Tutu.                      

Would work better with you though. Just imagine a

Tinca TuTu

[Scapanapper]

ziggy searchfield:

MCMLXII, thats when i was born, what about you ?

I was born in the binary year.

1110100101 :confused:

 

Cheers Scapa

 

[ 30. September 2004, 08:41 AM: Message edited by: Scapanapper ]

[Paul_D]

Blimey....1866 - How many telegrams have you had from the Queen now then scapa?

[Scapanapper]

Paul_D:

Blimey....1866 - How many telegrams have you had from the Queen now then scapa?

Edited original (Took last 0 out) but not quite as old as your answer.

[Newt]

1110100101

So born in 3A5 (that's 933 for you decimal fans) then. That would be 3A5 AD or BC?

 

(try again but use http://www.math.com/students/converters/so...source/base.htm to calculate - lots quicker than by hand and Excel's BIN2DEC function chokes on a 10 binary digit number)

[Scapanapper]

Tried the converter Newt and I was right!!

11110100101 = 1957

You had I worried that I are not as brilliant as wot I thinks I is.

 

Cheers

Scapa

 

[ 30. September 2004, 10:39 AM: Message edited by: Scapanapper ]

[Scapanapper]

Newt what is the 3A5 system??

[Newt]

Scapanapper:

I was born in the binary year.

1110100101

Different than "Tried the converter Newt and I was right!!

11110100101 = 1957

 

I agree that 11110100101 = 1957 but your original has one less leading number "one".

 

1110100101 (binary / base 2) = 933 (decimal / base 10) = 3A5 (hexadecimal / base 16)

 

BTW - 1957 (decimal) would be 7A5 (hexadecimal)

[Scapanapper]

You're quite right Newt. The problem is obviously that I can work stuff out on paper but have difficulty typing it

Sorry.

 

How does hexadecimal work?

 

[ 30. September 2004, 11:16 AM: Message edited by: Scapanapper ]

[Paul_D]

Same as Binary effectively but to the power of 16......7A5 = 7 x16 x16 + 10 x 16 + 5 (where A effectively = 10, B= 11, C= 12 etc) Simple! :confused: